The internal energy of a thermodynamic system is given by $$U=a s^{4 / 3} V^\alpha$$ where $$\mathrm{s}$$ is entropy, $$\mathrm{V}$$ is volume and '$$\mathrm{a}$$' and '$$\alpha$$' are constants. The value of $$\alpha$$ is

Six molecules of an ideal gas have velocities 1, 3, 5, 5, 6 and 5 m/s respectively. At any given temperature, if $$\mathrm{\overline V}$$ and $$\mathrm{V_{rms}}$$ represent average and rms speed of the molecules, then

A given quantity of gas is taken from A to C in two ways; a) directly from A $$\to$$ C along a straight line and b) in two steps, from A $$\to$$ B and then from B $$\to$$ C. Work done and heat absorbed along the direct path A $$\to$$ C is 200 J and 280 J respectively.

If the work done along A $$\to$$ B $$\to$$ C is 80 J, then heat absorbed along this path is,

Two substances A and B of same mass are heated at constant rate. The variation of temperature $$\theta$$ of the substances with time t is shown in the figure. Choose the correct statement.