1
TS EAMCET 2020 (Online) 10th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

An ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ with eccentricity $\frac{2 \sqrt{2}}{3}$ is inscribed in a circle $x^2+y^2=18$ such that the length of its major axis is equal to the diameter of this circle. The locus of the poles of all the tangents of the circle with respect to the ellipse is

A

$x^2+y^2=\frac{8}{9}$

B

$18 x+\frac{2 y}{9}=1$

C

$\frac{x^2}{18}+\frac{y^2}{9}=1$

D

$\frac{x^2}{18}+\frac{9 y^2}{2}=1$

2
TS EAMCET 2020 (Online) 10th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

The eccentricity of an ellipse passing through $(3 \sqrt{2}, \sqrt{10})$ with foci at $(-4,0)$ and $(4,0)$ is

A

$\frac{1}{2}$

B

$\frac{2}{3}$

C

$\frac{\sqrt{2}}{3}$

D

$\frac{1}{\sqrt{3}}$

3
TS EAMCET 2020 (Online) 10th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

If the product of the lengths of the perpendiculars drawn from the foci to the tangent $y=\frac{-3}{4} x+3 \sqrt{2}$ of the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ is 9 , then the eccentricity of that ellipse is

A

$\frac{\sqrt{2}}{3}$

B

$\frac{\sqrt{5}}{6}$

C

$\frac{1}{9}$

D

$\frac{\sqrt{7}}{4}$

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