1
TS EAMCET 2022 (Online) 20th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

$A=\left[\begin{array}{lll}1 & 2 & 3 \\ 4 & 3 & 2\end{array}\right]$, then $\left(A+A^T\right)\left(A-A^T\right)=$

A

$4\left[\begin{array}{lll}3 & 2 & -3 \\ 3 & 0 & -3 \\ 3 & 2 & -3\end{array}\right]$

B

$\left[\begin{array}{lll}12 & 8 & 12 \\ 12 & 0 & 12 \\ 12 & 8 & 12\end{array}\right]$

C

$4\left[\begin{array}{ccc}3 & -2 & -3 \\ 3 & 0 & -3 \\ 3 & -2 & -3\end{array}\right]$

D

$\left[\begin{array}{lll}-12 & 8 & 12 \\ -12 & 0 & 12 \\ -12 & 8 & 12\end{array}\right]$

2
TS EAMCET 2022 (Online) 20th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $f(x)=\left|\begin{array}{ccc}x & x+1 & x+3 \\ x+2 & x+4 & x+7 \\ x+6 & x+9 & x+13\end{array}\right|$, then $f(5)=$

A

-15

B

10

C

-2

D

0

3
TS EAMCET 2022 (Online) 20th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let $A=\left[\begin{array}{lll}2 & 1 & 1 \\ 0 & 1 & 0 \\ 1 & 1 & 2\end{array}\right]$. If $A^{-1}=\alpha A^2+\beta A+\gamma I$, where $\alpha, \beta$ and $\gamma$ are real numbers and $I$ is a $3 \times 3$ identity matrix, then $17 \alpha+5 \beta+\gamma=$

A

-1

B

$\frac{-1}{3}$

C

$\frac{2}{3}$

D

3

4
TS EAMCET 2022 (Online) 20th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

For a system of simultaneous linear equations, if $A X=\left[\begin{array}{l}1 \\ 1 \\ 2\end{array}\right], \operatorname{Adj} A=\left[\begin{array}{ccc}1 & -1 & -1 \\ 1 & 1 & -1 \\ 1 & 1 & 1\end{array}\right]$ and $\operatorname{det} A>0$, then $X=$

A

$\left[\begin{array}{c}-1 \\ 0 \\ 2\end{array}\right]$

B

$\left[\begin{array}{l}1 \\ 1 \\ 2\end{array}\right]$

C

$\left[\begin{array}{c}0 \\ -1 \\ -1\end{array}\right]$

D

$\left[\begin{array}{l}2 \\ 1 \\ 1\end{array}\right]$

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