1
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25
Change Language

A charged particle in a uniform magnetic field $$\vec{B}=B_{0} \hat{k}$$ starts moving from the origin with velocity $$v=3 \hat{\mathrm{i}}+4 \hat{\mathrm{k}} ~\mathrm{m} / \mathrm{s}$$. The trajectory of the particle and the time $$t$$ at which it reaches $$2 \mathrm{~m}$$ above $$\mathrm{x}-\mathrm{y}$$ plane are,

A
Circular path $$1 / 2 ~\mathrm{sec}$$.
B
Helical path, $$1 / 2$$ sec.
C
Circular path, $$2 / 3 ~\mathrm{sec}$$.
D
Helidatpath, $$2 / 3 ~\mathrm{sec}$$.
2
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25
Change Language

WB JEE 2023 Physics - Electromagnetic Induction Question 3 English

A circular coil is placed near a current carrying conductor, both lying on the plane of the paper. The current is flowing through the conductor in such a way that the induced current in the loop is clockwise as shown in the figure. The current in the wire is,

A
time dependent and downward.
B
steady and upward.
C
time dependent and upward.
D
An alternating current.
3
WB JEE 2022
MCQ (Single Correct Answer)
+1
-0.25
Change Language

In a closed circuit there is only a coil of inductance L and resistance 100 $$\Omega$$. The coil is situated in a uniform magnetic field. All on a sudden, the magnetic flux linked with the circuit changes by 5 Weber. What amount of charge will flow in the circuit as a result?

A
500 C
B
0.05 C
C
20 C
D
Value of L is to be known to find the charge flown
4
WB JEE 2021
MCQ (Single Correct Answer)
+2
-0.5
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For a plane electromagnetic wave, the electric field is given by

$$ \overrightarrow{E} = 90\sin (0.5 \times {10^3}x + 1.5 \times {10^{11}}t)\widehat k$$ V/m. The corresponding magnetic field B will be
A
$$\overrightarrow{B} = 3 \times {10^{ - 7}}\sin (0.5 \times {10^3}x + 1.5 \times {10^{11}}t)\widehat i$$ T
B
$$\overrightarrow{B} = 3 \times {10^{ - 7}}\sin (0.5 \times {10^3}x + 1.5 \times {10^{11}}t)\widehat j$$ T
C
$$\overrightarrow{B} = 27 \times {10^9}\sin (0.5 \times {10^3}x + 1.5 \times {10^{11}}t)\widehat j$$ T
D
$$\overrightarrow{B} = 3 \times {10^{ - 7}}\sin (0.5 \times {10^3}x + 1.5 \times {10^{11}}t)\widehat k$$ T
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