WB JEE 2023 | Electromagnetic Induction Question 4 | Physics

WB JEE 2023

MCQ (Single Correct Answer)

-0.25

A charged particle in a uniform magnetic field $$\vec{B}=B_{0} \hat{k}$$ starts moving from the origin with velocity $$v=3 \hat{\mathrm{i}}+4 \hat{\mathrm{k}} ~\mathrm{m} / \mathrm{s}$$. The trajectory of the particle and the time $$t$$ at which it reaches $$2 \mathrm{~m}$$ above $$\mathrm{x}-\mathrm{y}$$ plane are,

Circular path $$1 / 2 ~\mathrm{sec}$$.

Helical path, $$1 / 2$$ sec.

Circular path, $$2 / 3 ~\mathrm{sec}$$.

Helidatpath, $$2 / 3 ~\mathrm{sec}$$.

WB JEE 2022

MCQ (Single Correct Answer)

-0.25

In a closed circuit there is only a coil of inductance L and resistance 100 $$\Omega$$. The coil is situated in a uniform magnetic field. All on a sudden, the magnetic flux linked with the circuit changes by 5 Weber. What amount of charge will flow in the circuit as a result?

500 C

0.05 C

20 C

Value of L is to be known to find the charge flown

WB JEE 2021

MCQ (Single Correct Answer)

-0.5

For a plane electromagnetic wave, the electric field is given by

$$ \overrightarrow{E} = 90\sin (0.5 \times {10^3}x + 1.5 \times {10^{11}}t)\widehat k$$ V/m. The corresponding magnetic field B will be

$$\overrightarrow{B} = 3 \times {10^{ - 7}}\sin (0.5 \times {10^3}x + 1.5 \times {10^{11}}t)\widehat i$$ T

$$\overrightarrow{B} = 3 \times {10^{ - 7}}\sin (0.5 \times {10^3}x + 1.5 \times {10^{11}}t)\widehat j$$ T

$$\overrightarrow{B} = 27 \times {10^9}\sin (0.5 \times {10^3}x + 1.5 \times {10^{11}}t)\widehat j$$ T

$$\overrightarrow{B} = 3 \times {10^{ - 7}}\sin (0.5 \times {10^3}x + 1.5 \times {10^{11}}t)\widehat k$$ T

WB JEE 2020

MCQ (Single Correct Answer)

-0.25

Consider a conducting wire of length L bent in the form of a circle of radius R and another conductor of length a (a < < R) is bent in the form of a square. The two loops are then placed in same plane such that the square loop is exactly at the centre of the circular loop. What will be the mutual inductance between the two loops?

$${\mu _0}{{\pi {a^2}} \over L}$$

$${\mu _0}{{\pi {a^2}} \over 16L}$$

$${\mu _0}{{\pi {a^2}} \over 4L}$$

$${\mu _0}{{{a^2}} \over {4\pi L}}$$

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