WB JEE 2021 | Units & Measurements Question 12 | Physics

WB JEE 2021

MCQ (Single Correct Answer)

-0.25

From dimensional analysis, the Rydberg constant can be expressed in terms of electric charge (e), mass (m) and Planck constant (h) as [consider $${1 \over {4\pi {\varepsilon _0}}} \equiv 1$$ unit]

$${{{h^2}} \over {m{e^2}}}$$

$${{m{e^4}} \over {{h^2}}}$$

$${{{m^2}{e^4}} \over {{h^2}}}$$

$${{m{e^2}} \over {{h^2}}}$$

WB JEE 2020

MCQ (Single Correct Answer)

-0.25

The frequency v of the radiation emitted by an atom when an electron jumps from one orbit to another is given by v = k$$\delta $$E, where k is a constant and $$\delta $$E is the change in energy level due to the transition. Then, dimension of k is

$${\left[ {M{L^2}{T^{ - 2}}} \right]}$$

the same dimension of angular momentum

$${\left[ {M{L^2}{T^{ - 1}}} \right]}$$

$$\left[ {{M^{ - 1}}{L^{ - 2}}T} \right]$$

WB JEE 2019

MCQ (Single Correct Answer)

-0.25

The correct dimensional formula for impulse is given by

ML²t^$$-$$2

MLT^$$-$$1

ML²t^$$-$$1

MLT^$$-$$2

WB JEE 2019

MCQ (Single Correct Answer)

-0.25

The density of the material of a cube can be estimated by measuring its mass and the length of one of its sides. If the maximum error in the measurement of mass and length are 0.3% and 0.2% respectively, the maximum error in the estimation of the density of the cube is approximately

1.1%

0.5%

0.9%

0.7%

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