MHT CET 2025 25th April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2025 25th April Morning Shift

MCQ (Single Correct Answer)

-0

An a. c. voltage is applied to pure inductor. The current in the inductor

leads the voltage by $\left(\frac{\pi}{4}\right)^c$

leads the voltage by $\left(\frac{\pi}{2}\right)^c$

lags behind the voltage by $\left(\frac{\pi}{2}\right)^c$

lags behind the voltage by $\left(\frac{3 \pi}{4}\right)^c$

MHT CET 2025 25th April Morning Shift

MCQ (Single Correct Answer)

-0

During the isothermal expansion, a confined ideal gas does $(-150) \mathrm{J}$ of work against its surroundings. This means that

150 J of heat has been added to the gas

150 J of heat has been removed from the gas

300 J of heat has been added to the gas

no heat is transferred because the process is isothermal

MHT CET 2025 25th April Morning Shift

MCQ (Single Correct Answer)

-0

A single slit diffraction pattern is formed with light of wavelength $6384 \mathop {\rm{A}}\limits^{\rm{o}}$. The second secondary maximum for this wavelength coincides with the third secondary maximum in the pattern for light of wavelength ' $\lambda_0$ '. The value of ' $\lambda_0$ ' is

$4242 \mathop {\rm{A}}\limits^{\rm{o}}$

$4560 \mathop {\rm{A}}\limits^{\rm{o}}$

$5474 \mathop {\rm{A}}\limits^{\rm{o}}$

$6384 \mathop {\rm{A}}\limits^{\rm{o}}$

MHT CET 2025 25th April Morning Shift

MCQ (Single Correct Answer)

-0

When a metal surface is illuminated by light of wavelength $\lambda_1$ and $\lambda_2$, the maximum velocities of photoelectrons ejected are V and 2 V respectively. The work function of the metal is ( $\mathrm{h}=$ Planck's constant, $\mathrm{c}=$ velocity of light, $\lambda_1>\lambda_2$ )

$\frac{\mathrm{hc}}{2 \lambda_1 \lambda_2}\left(\lambda_1-\lambda_2\right)$

$\frac{\mathrm{hc}}{\lambda_1 \lambda_2}\left(\lambda_1-\lambda_2\right)$

$\frac{\mathrm{hc}}{\lambda_1 \lambda_2}\left(\lambda_1+\lambda_2\right)$

$\frac{\mathrm{hc}}{3 \lambda_1 \lambda_2}\left(4 \lambda_2-\lambda_1\right)$

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