1
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

$$ \lim\limits_{x \rightarrow 5} \frac{\sqrt{2-2 \cos \left(x^2-12 x+35\right)}}{(x-5)}=\ldots \ldots $$

A
$\frac{2}{-5}$
B
-2
C
$\frac{-1}{2}$
D
-5
2
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If ${ }^n \mathrm{C}_0+\frac{1}{2}{ }^n \mathrm{C}_1+\frac{1}{3}{ }^n \mathrm{C}_2$$$+\ldots \frac{1}{n}^n C_{n-1}+\frac{1}{n+1}{ }^n C_n=\frac{1023}{10} \,\,\, then \,\,\,\,\mathrm{n}=$$

A
7
B
8
C
9
D
10
3
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

A pair of fair dice is thrown 4 times. If getting the same number on both dice is considered as a success, then the probability of two successes are

A
$\frac{25}{216}$
B
$\frac{25}{36}$
C
$\frac{25}{108}$
D
$\frac{25}{104}$
4
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The position vectors of the points $A, B, C$ are $\hat{i}+2 \hat{j}-\hat{k}, \hat{i}+\hat{j}+\hat{k}, 2 \hat{i}+3 \hat{j}+2 \hat{k}$ respectively. If $A$ is chosen as the origin, then the cross product of position vectors of $B$ and $C$ are

A
$-5 \hat{\mathrm{i}}+2 \hat{\mathrm{j}}+\hat{\mathrm{k}}$
B
$-\hat{\mathrm{i}}+0 \hat{\mathrm{j}}-\hat{\mathrm{k}}$
C
$\hat{\mathrm{i}}-\hat{\mathrm{k}}$
D
$5 \hat{\mathrm{i}}-2 \hat{\mathrm{j}}-\hat{\mathrm{k}}$
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