1
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
A single slit diffraction pattern is formed with light of wavelength $6384 \mathop {\rm{A}}\limits^{\rm{o}}$. The second secondary maximum for this wavelength coincides with the third secondary maximum in the pattern for light of wavelength ' $\lambda_0$ '. The value of ' $\lambda_0$ ' is
A
$4242 \mathop {\rm{A}}\limits^{\rm{o}}$
B
$4560 \mathop {\rm{A}}\limits^{\rm{o}}$
C
$5474 \mathop {\rm{A}}\limits^{\rm{o}}$
D
$6384 \mathop {\rm{A}}\limits^{\rm{o}}$
2
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

When a metal surface is illuminated by light of wavelength $\lambda_1$ and $\lambda_2$, the maximum velocities of photoelectrons ejected are V and 2 V respectively. The work function of the metal is ( $\mathrm{h}=$ Planck's constant, $\mathrm{c}=$ velocity of light, $\lambda_1>\lambda_2$ )

A
$\frac{\mathrm{hc}}{2 \lambda_1 \lambda_2}\left(\lambda_1-\lambda_2\right)$
B
$\frac{\mathrm{hc}}{\lambda_1 \lambda_2}\left(\lambda_1-\lambda_2\right)$
C
$\frac{\mathrm{hc}}{\lambda_1 \lambda_2}\left(\lambda_1+\lambda_2\right)$
D
$\frac{\mathrm{hc}}{3 \lambda_1 \lambda_2}\left(4 \lambda_2-\lambda_1\right)$
3
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

A point mass ' $m$ ' attached at one end of a massless, inextensible string of length ' $l$ ' performs a vertical circular motion and the string rotates in vertical plane, as shown in the diagram. The increase in the centripetal acceleration of the point mass when it moves from point A to point C is

[ $\mathrm{g}=$ acceleration due to gravity.]

MHT CET 2025 25th April Morning Shift Physics - Circular Motion Question 3 English
A
3 g
B
2 g
C
g
D
$\frac{\mathrm{g}}{2}$
4
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

A body cools from $80^{\circ} \mathrm{C}$ to $50^{\circ} \mathrm{C}$ in 5 min . In the next time of ' t ' in, the body continues to cool from $50^{\circ} \mathrm{C}$ to $30^{\circ} \mathrm{C}$. The total time taken by the body to cool from $80^{\circ} \mathrm{C}$ to $30^{\circ} \mathrm{C}$ is [The temperature of the surroundings is $20^{\circ} \mathrm{C}$.]

A
10 min
B
7.5 min
C
15.0 min
D
12.5 min
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