1
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The principal value of $\cos ^{-1}\left[\frac{1}{\sqrt{2}}\left(\cos \frac{9 \pi}{10}-\sin \frac{9 \pi}{10}\right)\right]$ is

A
$\frac{3 \pi}{20}$
B
$\frac{17 \pi}{20}$
C
$\frac{7 \pi}{10}$
D
$\frac{\pi}{10}$
2
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The length of the foot of the perpendicular from the point $\left(1, \frac{3}{2}, 2\right)$ to the plane $2 x-2 y+4 z+17=0$ is

A
$\sqrt{6}$ units
B
$3 \sqrt{3}$ units
C
$4 \sqrt{3}$ units
D
$2 \sqrt{6}$ units
3
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

A tetrahedron has vertices $\mathrm{O}(0,0,0), \mathrm{A}(1,2,1)$, $B(2,1,3), C(-1,1,2)$. Then the angle between the faces OAB and ABC will be

A
$\cos ^{-1}\left(\frac{19}{35}\right)$
B
$\cos ^{-1}\left(\frac{1}{35}\right)$
C
$\cos ^{-1}\left(\frac{9}{35}\right)$
D
$\cos ^{-1}\left(\frac{4}{35}\right)$
4
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $A=\left[\begin{array}{lll}3 & -3 & 4 \\ 2 & -3 & 4 \\ 0 & -1 & 1\end{array}\right]_{3 \times 3}$, then $A^{-1}=$

A
A
B
$\mathrm{A}^2$
C
$\mathrm{A}^3$
D
$\mathrm{A}^4$
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