1
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A simple pendulum with bob of mass m and conducting wire of length $L$ swings under gravity through an angle $\theta$. The component of earth's magnetic field in the direction perpendicular to swing is B . Maximum e.m.f. induced across the pendulum is ( $\mathrm{g}=$ acceleration due to gravity)

A
$2 \mathrm{BL}(\sqrt{\mathrm{gL}})\left(\sin \frac{\theta}{2}\right)$
B
$\mathrm{BL}(\sqrt{\mathrm{gL}})\left(\sin \frac{\theta}{2}\right)$
C
$\mathrm{BL}(\sqrt{\mathrm{gL}})^2\left(\sin \frac{\theta}{2}\right)$
D
$2 \mathrm{BL}(\sqrt{\mathrm{gL}})\left(\sin ^2 \frac{\theta}{2}\right)$
2
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

In a cyclic process, work done by the system is

A
more than the heat given to the system.
B
equal to the heat given to the system.
C
zero.
D
independent of the heat given to the system.
3
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A metal sphere cools at a rate of $1.5^{\circ} \mathrm{C} / \mathrm{min}$ when its temperature is $80^{\circ} \mathrm{C}$. When the temperature of the sphere is $40^{\circ} \mathrm{C}$, its rate of cooling is $0.3^{\circ} \mathrm{C} / \mathrm{min}$. The temperature of the surrounding $\left(\theta_0\right)$ is

A
$30^{\circ} \mathrm{C}$
B
$35^{\circ} \mathrm{C}$
C
$25^{\circ} \mathrm{C}$
D
$27^{\circ} \mathrm{C}$
4
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

The resultant logic gate from the combination of following gates is

MHT CET 2025 20th April Evening Shift Physics - Semiconductor Devices and Logic Gates Question 1 English
A
OR
B
NAND
C
AND
D
NOR
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