1
MHT CET 2024 15th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $x=2 \cos \theta-\cos 2 \theta$ and $y=2 \sin \theta-\sin 2 \theta$, then $\frac{\mathrm{d}^2 y}{d x^2}$ is equal to

A
$\frac{3}{2} \tan \frac{3 \theta}{2}$
B
$\frac{3}{2} \sec \frac{3 \theta}{2} \tan \frac{3 \theta}{2}$
C
$\frac{3}{2} \sec ^2 \frac{3 \theta}{2}$
D
$\sec ^2 \frac{3 \theta}{2}$
2
MHT CET 2024 15th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

$2 \pi-\left(\sin ^{-1} \frac{4}{5}+\sin ^{-1} \frac{5}{13}+\sin ^{-1} \frac{16}{65}\right)$ is equal to

A
$\frac{\pi}{2}$
B
$\frac{5 \pi}{4}$
C
$\frac{7 \pi}{4}$
D
$\frac{3 \pi}{2}$
3
MHT CET 2024 15th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If two sides of a square are $4 x+3 y-20=0$ and $4 x+3 y+15=0$, then the area of the square is

A
36 sq. units
B
16 sq. units
C
4 sq. units
D
49 sq. units
4
MHT CET 2024 15th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

Twenty meters of wire is available for fencing off a flower-bed in the form of a circular sector. Then the maximum area (in sq.m) of the flowerbed is

A
30
B
12.5
C
25
D
10
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