1
MHT CET 2024 15th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

Let $\mathrm{L}_1: \frac{x+2}{5}=\frac{y-3}{2}=\frac{\mathrm{z}-6}{1}$ and $\mathrm{L}_2: \frac{x-3}{4}=\frac{y+2}{3}=\frac{z-3}{5}$ be the given lines. Then the unit vector perpendicular to both $\mathrm{L}_1$ and $\mathrm{L}_2$ is

A
$\frac{-\hat{i}-3 \hat{j}+\hat{k}}{11}$
B
$\frac{\hat{i}-3 \hat{j}+\hat{k}}{11}$
C
$\frac{\hat{i}+3 \hat{j}-\hat{k}}{11}$
D
$\frac{\hat{i}+3 \hat{j}+\hat{k}}{11}$
2
MHT CET 2024 15th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

A multiple choice examination has 5 questions. Each question has three alternative answers of which exactly one is correct. The probability that a student will get 4 or more correct answers just by guessing is

A
$\frac{17}{243}$
B
$\frac{13}{243}$
C
$\frac{11}{243}$
D
$\frac{10}{243}$
3
MHT CET 2024 15th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The perpendicular distance from the origin to the plane containing the two lines $\frac{x+2}{3}=\frac{y-2}{5}=\frac{z+5}{7}$ and $\frac{x-1}{1}=\frac{y-4}{4}=\frac{z+4}{7}$, is

A
$\frac{11}{\sqrt{6}}$ units
B
$11 \sqrt{6}$ units
C
$11$ units
D
$6 \sqrt{11}$ units
4
MHT CET 2024 15th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The number of integral values of k for which the equation $7\cos x+5\sin x=2k+1$ has a solution, is

A
4
B
8
C
10
D
12
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