MHT CET 2023 14th May Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2023 14th May Morning Shift

MCQ (Single Correct Answer)

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Identify the product '$$\mathrm{B}$$' in the following reaction. Toluene $$\xrightarrow[\mathrm{CS}_2]{\text { Chromylchloride }} \mathrm{A} \xrightarrow{\mathrm{H}_3 \mathrm{O}^{+}}\mathrm{B}$$

Benzal chloride

Benzaldehyde

Benzyl alcohol

Benzoic acid

MHT CET 2023 14th May Morning Shift

MCQ (Single Correct Answer)

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The negation of the statement

"The number is an odd number if and only if it is divisible by 3."

The number is an odd number but not divisible by 3 or the number is divisible by 3 but not odd.

The number is not an odd number iff it is not divisible by 3.

The number is not an odd number but it is divisible by 3.

The number is not an odd number or is not divisible by 3 but the number is divisible by 3 or odd.

MHT CET 2023 14th May Morning Shift

MCQ (Single Correct Answer)

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Two cards are drawn successively with replacement from well shuffled pack of 52 cards, then the probability distribution of number of queens is

$$\mathrm{X}=x$$	0	1	2
$$\mathrm{P[X=}x]$$	$$\frac{144}{169}$$	$$\frac{24}{169}$$	$$\frac{1}{169}$$

$$\mathrm{X}=x$$	0	1	2
$$\mathrm{P[X=}x]$$	$$\frac{1}{169}$$	$$\frac{24}{169}$$	$$\frac{144}{169}$$

$$\mathrm{X}=x$$	0	1	2
$$\mathrm{P[X=}x]$$	$$\frac{24}{169}$$	$$\frac{1}{169}$$	$$\frac{144}{169}$$

$$\mathrm{X}=x$$	0	1	2
$$\mathrm{P[X=}x]$$	$$\frac{1}{169}$$	$$\frac{25}{169}$$	$$\frac{143}{169}$$

MHT CET 2023 14th May Morning Shift

MCQ (Single Correct Answer)

-0

For an initial screening of an entrance exam, a candidate is given fifty problems to solve. If the probability that the candidate can solve any problem is $$\frac{4}{5}$$, then the probability, that he is unable to solve less than two problems, is

$$\frac{201}{5}\left(\frac{1}{5}\right)^{49}$$

$$\frac{316}{25}\left(\frac{4}{5}\right)^{48}$$

$$\frac{54}{5}\left(\frac{4}{5}\right)^{49}$$

$$\frac{164}{25}\left(\frac{1}{5}\right)^{48}$$

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