1
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The bob of simple pendulum of length '$$L$$' is released from a position of small angular displacement $$\theta$$. Its linear displacement at time '$$\mathrm{t}$$' is ( $$\mathrm{g}=$$ acceleration due to gravity)

A
$$L \theta \cos \left[\sqrt{\frac{g}{L}} \cdot t\right]$$
B
$$L \theta \sin \left[2 \pi \sqrt{\frac{g}{L}} \cdot t\right]$$
C
$$L \theta \cos \left[2 \pi \sqrt{\frac{g}{L}} \cdot t\right]$$
D
$$L \theta \sin \left[\sqrt{\frac{g}{L}} \cdot t\right]$$
2
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The value of acceleration due to gravity at a depth '$$d$$' from the surface of earth and at an altitude '$$h$$' from the surface of earth are in the ratio

A
$$1: 1$$
B
$$\frac{R-2 h}{R-d}$$
C
$$\frac{R-d}{R-2 h}$$
D
$$\frac{\mathrm{R}-\mathrm{d}}{\mathrm{R}-\mathrm{h}}$$
3
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A magnetic field of $$2 \times 10^{-2} \mathrm{~T}$$ acts at right angles to a coil of area $$100 \mathrm{~cm}^2$$ with 50 turns. The average e.m.f. induced in the coil is $$0.1 \mathrm{~V}$$, when it is removed from the field in time '$$t$$'. The value of '$$t$$' is

A
$$2 \times 10^{-3} \mathrm{~s}$$
B
$$0.5 \mathrm{~s}$$
C
$$0.1 \mathrm{~s}$$
D
$$1 \mathrm{~s}$$
4
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

In Young's double slit experiment, $$8^{\text {th }}$$ maximum with wavelength '$$\lambda_1$$' is at a distance '$$d_1$$' from the central maximum and $$6^{\text {th }}$$ maximum with wavelength '$$\lambda_2$$' is at a distance '$$\mathrm{d}_2$$'. Then $$\frac{\mathrm{d}_2}{\mathrm{~d}_1}$$ is

A
$$\frac{3 \lambda_1}{4 \lambda_2}$$
B
$$\frac{3 \lambda_2}{4 \lambda_1}$$
C
$$\frac{4 \lambda_1}{3 \lambda_2}$$
D
$$\frac{4 \lambda_2}{3 \lambda_1}$$
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