MHT CET 2023 14th May Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2023 14th May Morning Shift

MCQ (Single Correct Answer)

-0

A wire of length $$3 \mathrm{~m}$$ connected in the left gap of a meter-bridge balances $$8 \Omega$$ resistance in the right gap at a point, which divides the bridge wire in the ratio $$3: 2$$. The length of the wire corresponding to resistance of $$1 \Omega$$ is

$$1 \mathrm{~m}$$

$$0.75 \mathrm{~m}$$

$$0.5 \mathrm{~m}$$

$$0.25 \mathrm{~m}$$

MHT CET 2023 14th May Morning Shift

MCQ (Single Correct Answer)

-0

By adding soluble impurity in a liquid, angle of contact

decreases

increases

remains unchanged

first increases and then decreases

MHT CET 2023 14th May Morning Shift

MCQ (Single Correct Answer)

-0

For a common emitter configuration, if '$$\alpha$$' and '$$\beta$$' have their usual meanings, the incorrect relation between '$$\alpha$$' and '$$\beta$$' is

$$\frac{1}{\alpha}=\frac{1}{\beta}+1$$

$$\alpha=\frac{\beta}{1-\beta}$$

$$\alpha=\frac{\beta}{1+\beta}$$

$$\frac{1}{\beta}=\frac{1}{\alpha}-1$$

MHT CET 2023 14th May Morning Shift

MCQ (Single Correct Answer)

-0

A simple pendulum of length '$$l$$' and a bob of mass '$$\mathrm{m}$$' is executing S.H.M. of small amplitude '$$A$$'. The maximum tension in the string will be ($$\mathrm{g}=$$ acceleration due to gravity)

$$2 \mathrm{~mg}$$

$$\mathrm{mg}\left[1+\left(\frac{\mathrm{A}}{\ell}\right)^2\right]$$

$$\mathrm{mg}\left[1+\left(\frac{\mathrm{A}}{\ell}\right)\right]^2$$

$$m g\left[1+\left(\frac{\mathrm{A}}{\ell}\right)\right]$$

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