GATE ME 2015 Set 3 | GATE ME Year Wise Previous Years Questions

GATE ME 2015 Set 3

MCQ (Single Correct Answer)

-0.3

For the same material and the mass, which of the following configurations of flywheel will have maximum mass moment of inertia about the axis of rotation $$OO’$$ passing through the center of gravity

GATE ME 2015 Set 3 Strength of Materials - Moment of Inertia Question 5 English Option 1

GATE ME 2015 Set 3 Strength of Materials - Moment of Inertia Question 5 English Option 2

GATE ME 2015 Set 3

MCQ (Single Correct Answer)

-0.6

The value of moment of inertia of the section shown in the figure about the axis-$$XX$$ is GATE ME 2015 Set 3 Strength of Materials - Moment of Inertia Question 3 English

GATE ME 2015 Set 3 Strength of Materials - Moment of Inertia Question 3 English

$$All$$ $$dimensions$$ $$are$$ $$in$$ $$'mm'$$

$$8.5050 \times {10^6}\,m{m^4}$$

$$6.8850 \times {10^6}\,m{m^4}$$

$$7.7625 \times {10^6}\,m{m^4}$$

$$8.5725 \times {10^6}\,m{m^4}$$

GATE ME 2015 Set 3

Numerical

-0

A cylindrical tank with closed ends is filled with compressed air at a pressure of $$500 kP$$a. The inner radius of the tank is $$2 m,$$ and it has wall thickness of $$10 mm.$$ The magnitude of maximum in-plane shear stress (in $$MP$$a) is ________

Your input ____

GATE ME 2015 Set 3

MCQ (Single Correct Answer)

-0.3

In the figure, link $$2$$ rotates with constant angular velocity $${{\omega _2}}$$. A slider link $$3$$ moves outwards with a constant relative velocity $${V_{Q/P,}}$$ where $$Q$$ is a point on slider $$3$$ and $$p$$ is a point on link $$2.$$ The magnitude and direction of Coriolis component of acceleration is given by GATE ME 2015 Set 3 Theory of Machines - Analysis of Plane Mechanisms Question 40 English

GATE ME 2015 Set 3 Theory of Machines - Analysis of Plane Mechanisms Question 40 English

$${2{\omega _2}}$$ $${V_{Q/P;}}$$ direction of $${V_{Q/P}}$$ rotated by $${90^ \circ }$$ in the direction of $${{\omega _2}}.$$

$${{\omega _2}}$$ $${V_{Q/P}};$$ direction of $${V_{Q/P}}$$ rotated by $${90^ \circ }$$ in the direction of $${{\omega _2}}.$$

$${2{\omega _2}}$$ $${V_{Q/P}};$$ direction of $${V_{Q/P}}$$ rotated by $${90^ \circ }$$ Opposite to the direction of $${{\omega _2}}.$$

$${{\omega _2}}$$ $${V_{Q/P}};$$ direction of $${V_{Q/P}}$$ rotated by $${90^ \circ }$$ Opposite to the direction of $${{\omega _2}}.$$

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