GATE EE 2014 Set 1 | GATE EE Year Wise Previous Years Questions

GATE EE 2014 Set 1

MCQ (Single Correct Answer)

-0.3

In the Wien Bridge oscillator circuit shown in figure, the bridge is balanced when GATE EE 2014 Set 1 Analog Electronics - Feedback Amplifiers and Oscillator Circuits Question 8 English

GATE EE 2014 Set 1 Analog Electronics - Feedback Amplifiers and Oscillator Circuits Question 8 English

$${{{R_3}} \over {{R_4}}} = {{{R_1}} \over {{R_2}}},\,\,\,\omega = {1 \over {\sqrt {{R_1}{C_1}{R_2}{C_2}} }}$$

$${{{R_2}} \over {{R_1}}} = {{{C_2}} \over {{C_1}}},\,\,\,\omega = {1 \over {{R_1}{C_1}{R_2}{C_2}}}$$

$${{{R_3}} \over {{R_4}}} = {{{R_1}} \over {{R_2}}} + {{{C_2}} \over {{C_1}}},\,\,\,\omega = {1 \over {\sqrt {{R_1}{C_1}{R_2}{C_2}} }}$$

$${{{R_3}} \over {{R_4}}} + {{{R_1}} \over {{R_2}}} = {{{C_2}} \over {{C_1}}},\,\,\,\omega = {1 \over {{R_1}{C_1}{R_2}{C_2}}}$$

GATE EE 2014 Set 1

MCQ (Single Correct Answer)

-0.3

In the formation of Routh-Hurwitz array for a polynomial, all the elements of a row have zero values. This premature termination of the array indicates the presence of

only one root at the origin

imaginary roots

only positive real roots

only negative roots

GATE EE 2014 Set 1

Numerical

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For the given system, it is desired that the system be stable. The minimum value of $$\alpha $$ for this condition is _________ GATE EE 2014 Set 1 Control Systems - Routh Hurwitz Stability Question 10 English

Your input ____

GATE EE 2014 Set 1

MCQ (Single Correct Answer)

-0.3

The root locus of unity feedback system is shown in figure GATE EE 2014 Set 1 Control Systems - Root Locus Techniques Question 14 English

The closed loop transfer function of the system is

$${{C\left( s \right)} \over {R\left( s \right)}} = {K \over {\left( {s + 1} \right)\left( {s + 2} \right)}}$$

$${{C\left( s \right)} \over {R\left( s \right)}} = {{ - K} \over {\left( {s + 1} \right)\left( {s + 2} \right) + K}}$$

$${{C\left( s \right)} \over {R\left( s \right)}} = {K \over {\left( {s + 1} \right)\left( {s + 2} \right) - K}}$$

$${{C\left( s \right)} \over {R\left( s \right)}} = {K \over {\left( {s + 1} \right)\left( {s + 2} \right) + K}}$$

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