The following C function takes a single-linked list of integers as a parameter and rearranges the elements of the list. The function is called with the list containing the integers 1,2,3,4,5,6,7 in the given order. What will be the contents of the list after the function completes execution?

struct node { 
    int value; 
    struct node *next; 
}; 

Void rearrange (struct node *list ){ 
    struct node *p, * q; 
    int temp; 
    if( !list || !list-> next) return; 
    p = list; q = list->next; 
    while (q) { 
      temp = p->value; 
      p-> value = q ->value; 
      q-> value = temp; 
      p = q-> next; 
      q = p ? p->next : 0; 
    } 
}

A binary search tree contains the numbers 1, 2, 3, 4, 5, 6, 7, 8. When the tree is traversed in pre-order and the values in each node printed out, the sequence of values obtained is 5, 3, 1, 2, 4, 6, 8, 7. If the tree is traversed in post-order, the sequence obtained would be

In a complete k-ary tree, every internal node has exactly k children. The number of leaves in such a tree with n internal nodes is

In a binary tree, for every node the difference between the number of nodes in the left and right subtrees is at most 2. If the height of the tree is h > 0, then the minimum number of nodes in the tree is: