1
GATE CSE 2005
MCQ (Single Correct Answer)
+1
-0.3
The time complexity of computing the transitive closure of a binary relation on a set of elements is known to be:
A
O (n)
B
O (n log n)
C
O (n3/2)
D
O (n3)
2
GATE CSE 2005
MCQ (Single Correct Answer)
+2
-0.6
Consider the following C - function:
double foo(int n){
 int i;
 double sum;
 if(n == 0) return 1.0;
 sum = 0.0;
 for (i = 0; i < n; i++){
  sum += foo(i);
 }
 return sum;
}
Suppose we modify the above function foo() and store the values of foo(i), $$0 \le i \le n$$, as and when they are computed. With this modification, the time complexity for function foo() is significantly reduced. The space complexity of the modified function would be:
A
O(1)
B
O(n)
C
O(n2)
D
O(n!)
3
GATE CSE 2005
MCQ (Single Correct Answer)
+2
-0.6
A Priority-Queue is implemented as a Max-Heap. Initially, it has 5 elements. The level-order traversal of the heap is given below:
10, 8, 5, 3, 2
Two new elements '1' and '7' are inserted in the heap in that order, The level order traversal of the heap after the insertion of the elements is:
A
10, 8, 7, 5, 3, 2, 1
B
10, 8, 7, 2, 3, 1, 5
C
10, 8, 7, 1, 2, 3, 5
D
10, 8, 7, 3, 2, 1, 5
4
GATE CSE 2005
MCQ (Single Correct Answer)
+2
-0.6
Consider the following C - function:
double foo(int n){
 int i;
 double sum;
 if(n == 0) return 1.0;
 sum = 0.0;
 for (i = 0; i < n; i++){
  sum += foo(i);
 }
 return sum;
}
The space complexity of the above function is:
A
O(1)
B
O(n)
C
O(n!)
D
O(nn)
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