The maximum window size for data transmission using the selective reject protocol with n-bit frame sequence numbers is:

In a network of LANs connected by bridges, packets are sent from one LAN to another through intermediate bridges. Since more than one path may exist between two LANs, packets may have to be routed through multiple bridges. Why is the spanning tree algorithm used for bridge-routing?

Consider a three word machine instruction $$ADD$$ $$A$$ $$\left[ {{R_0}} \right],\,@\,B$$

The first operand (destination) ''$$A$$ $$\left[ {{R_0}} \right]''$$ uses indexed addressing mode with $${{R_0}}$$ as the index register. The second operand (source) $$''@B''$$ used indirect addressing mode. $$A$$ and $$B$$ are memory addresses residing at the second and the third words, respectively. The first word of the instruction specific the opcode, the index register designation and the source and destination addressing modes. During execution of $$ADD$$ instruction, the two operands are added and stored in the destination (first operand).

The number of memory cycles needed during the execution cycle of the instruction is

A $$5$$ stage pipelined $$CPU$$ has the following sequence of stages $$IF$$-Instruction fetch from instruction memory, $$RD$$-Instruction decode and register read, $$EX$$-Execute: $$ALU$$ operation for data and address computation, $$MA$$-Data memory access-for write access the register read and $$RD$$ stage it used, $$WB$$-Register write back.

Consider the following sequence of instructions:
$$\eqalign{ & {{\rm I}_1}:L\,R0,\,\,Loc1;\,R0 < \,\, = M\,[Loc1] \cr & {{\rm I}_2}:A\,R0,\,R0;\,\,\,\,\,\,R0 < \,\, = R0 + R0 \cr & {{\rm I}_3}:A\,R2,\,R0;\,\,\,\,\,\,R2 < \,\, = R2 - R0 \cr} $$

Let each stage takes one clock cycle.
What is the number of clock cycles taken to complete the above sequence of instructions starting from the fetch of $${{\rm I}_1}?$$