1
WB JEE 2019
MCQ (Single Correct Answer)
+1
-0.25
Change Language
S and T are the foci of an ellipse and B is the end point of the minor axis. If STB is equilateral triangle, the eccentricity of the ellipse is
A
$${1 \over 4}$$
B
$${1 \over 3}$$
C
$${1 \over 2}$$
D
$${2 \over 3}$$
2
WB JEE 2019
MCQ (Single Correct Answer)
+1
-0.25
Change Language
The equation of the directrices of the hyperbola $$3{x^2} - 3{y^2} - 18x + 12y + 2 = 0$$ is
A
$$x = 3 \pm \sqrt {{{13} \over 6}} $$
B
$$x = 3 \pm \sqrt {{{6} \over 13}} $$
C
$$x = 6 \pm \sqrt {{{13} \over 3}} $$
D
$$x = 6 \pm \sqrt {{{3} \over 13}} $$
3
WB JEE 2019
MCQ (Single Correct Answer)
+1
-0.25
Change Language
P is the extremity of the latusrectum of ellipse $$3{x^2} + 4{y^2} = 48$$ in the first quadrant. The eccentric angle of P is
A
$${\pi \over 8}$$
B
$${{3\pi } \over 4}$$
C
$${\pi \over 3}$$
D
$${{2\pi } \over 3}$$
4
WB JEE 2019
MCQ (Single Correct Answer)
+2
-0.5
Change Language
The length of conjugate axis of a hyperbola is greater than the length of transverse axis. Then, the eccentricity e is
A
$$ = \sqrt 2 $$
B
$$ > \sqrt 2 $$
C
$$ < \sqrt 2 $$
D
$$ < {1 \over {\sqrt 2 }}$$
WB JEE Subjects
EXAM MAP
Medical
NEET
Graduate Aptitude Test in Engineering
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CBSE
Class 12