WB JEE 2017 | Ellipse Question 28 | Mathematics

WB JEE 2017

MCQ (Single Correct Answer)

-0.5

Tangents are drawn to the ellipse $${{{x^2}} \over 9} + {{{y^2}} \over 5} = 1$$ at the ends of both latusrectum. The area of the quadrilateral, so formed is

27 sq units

$${{13} \over 2}$$ sq units

$${{15} \over 4}$$ sq units

45 sq units

WB JEE 2016

MCQ (Single Correct Answer)

-0.25

The line y = x + $$\lambda$$ is tangent to the ellipse 2x² + 3y² = 1. Then, $$\lambda$$ is

$$-$$2

$$\sqrt {{5 \over 6}} $$

$$\sqrt {{2 \over 3}} $$

WB JEE 2016

MCQ (Single Correct Answer)

-0.25

The equation of auxiliary circle of the ellipse $$16{x^2} + 25{y^2} + 32x - 100y = 284$$ is

$${x^2} + {y^2} + 2x - 4y - 20 = 0$$

$${x^2} + {y^2} + 2x - 4y = 0$$

$${(x + 1)^2} + {(y - 2)^2} = 400$$

$${(x + 1)^2} + {(y - 2)^2} = 255$$

WB JEE 2016

MCQ (Single Correct Answer)

-0.5

The points of the ellipse 16x² + 9y² = 400 at which the ordinate decreases at the same rate at which the abscissa increases is/are given by

$$\left( {3,{{16} \over 3}} \right)\left( { - 3, - {{16} \over 3}} \right)$$

$$\left( {3, - {{16} \over 3}} \right)\left( { - 3,{{16} \over 3}} \right)$$

$$\left( {{1 \over {16}},{1 \over 9}} \right)\left( { - {1 \over {16}}, - {1 \over 9}} \right)$$

$$\left( {{1 \over {16}}, - {1 \over 9}} \right)\left( { - {1 \over {16}},{1 \over 9}} \right)$$

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