1
TG EAPCET 2025 (Online) 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two adjacent sides of a triangle are represented by the vectors $2 \hat{\mathbf{i}}+\hat{\mathbf{j}}-2 \hat{\mathbf{k}}$ and $2 \sqrt{3} \hat{\mathbf{i}}-2 \sqrt{3} \hat{\mathbf{j}}+\sqrt{3} \hat{\mathbf{k}}$. Then, the least angle of the triangle and perimeter of the triangle are respectively.

A

$\frac{\pi}{3} ; 3(3+\sqrt{3})$

B

$\frac{\pi}{12} ; 6+3 \sqrt{2}$

C

$\frac{\pi}{2} ; 12$

D

$\frac{\pi}{6} ; 9+3 \sqrt{3}$

2
TG EAPCET 2025 (Online) 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A plane $\pi_1$ contains the vectors $\hat{\mathbf{i}}+\hat{\mathbf{j}}$ and $\hat{\mathbf{i}}+2 \hat{\mathbf{j}}$. Another plane $\pi_2$ contains the vectors $2 \hat{\mathbf{i}}-\hat{\mathbf{j}}$ and $3 \hat{\mathbf{i}}+2 \hat{\mathbf{k}}$. $\mathbf{a}$ is a vectors parallel to the line of intersection of $\pi_1$ and $\pi_2$. If the angle $\theta$ between $\mathbf{a}$ and $\hat{\mathbf{i}}-2 \hat{\mathbf{j}}+2 \hat{\mathbf{k}}$ is acute, then $\theta=$

A

$\frac{\pi}{2}$

B

$\frac{\pi}{4}$

C

$\cos ^{-1}\left(\frac{4}{3 \sqrt{5}}\right)$

D

$\cos ^{-1}\left(\frac{2}{\sqrt{5}}\right)$

3
TG EAPCET 2025 (Online) 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In a quadrilateral $A B C D, \mathbf{A}=\frac{2 \pi}{3}$ and $A C$ is the bisector of angle $\mathbf{A}$. If $15|\mathbf{A C}|=5|\mathbf{A D}|=3|\mathbf{A B}|$, then angle between $\mathbf{A B}$ and $\mathbf{B C}$ is

A

$\cos ^{-1}\left(\frac{\sqrt{3}}{\sqrt{7}}\right)$

B

$\cos ^{-1}\left(\frac{3 \sqrt{3}}{2 \sqrt{7}}\right)$

C

$\cos ^{-1}\left(\frac{4 \sqrt{3}}{5 \sqrt{7}}\right)$

D

$\cos ^{-1}\left(\frac{3 \sqrt{3}}{4 \sqrt{7}}\right)$

4
TG EAPCET 2025 (Online) 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$\mathbf{a}, \mathbf{b}, \mathbf{c}$ are three non- coplanar and mutually perpendicular vectors of same magnitude $K . r$ is any vectors satisfying $\mathbf{a} \times((\mathbf{r}-\mathbf{b}) \times \mathbf{a})+\mathbf{b} \times((\mathbf{r}-\mathbf{c}) \times \mathbf{b})+\mathbf{c} \times((\mathbf{r}-\mathbf{a}) \times \mathbf{c})=\mathbf{0}$, then $\mathbf{r}=$

A

$\frac{K^2(\mathbf{a}+\mathbf{b}+\mathbf{c})}{3 K^2-1}$

B

$\frac{\mathbf{a}+\mathbf{b}+\mathbf{c}}{2}$

C

$\frac{K(\mathbf{a}+\mathbf{b}+\mathbf{c})}{K+1}$

D

$\frac{\mathbf{a}+\mathbf{b}+\mathbf{c}}{K^2+1}$

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