1
WB JEE 2024
MCQ (Single Correct Answer)
+1
-0.25
Change Language

The position vector of a particle of mass $$\mathrm{m}$$ moving with a constant velocity $$\vec{v}$$ is given by $$\vec{r}=x(t) \hat{i}+b \hat{j}$$, where $$\mathrm{b}$$ is a constant. At an instant, $$\vec{r}$$ makes an angle $$\theta$$ with the $$x$$-axis as shown in the figure. The variation of the angular momentum of the particle about the origin with $$\theta$$ will be

WB JEE 2024 Physics - Rotational Motion Question 1 English

A
WB JEE 2024 Physics - Rotational Motion Question 1 English Option 1
B
WB JEE 2024 Physics - Rotational Motion Question 1 English Option 2
C
WB JEE 2024 Physics - Rotational Motion Question 1 English Option 3
D
WB JEE 2024 Physics - Rotational Motion Question 1 English Option 4
2
WB JEE 2024
MCQ (Single Correct Answer)
+1
-0.25
Change Language

WB JEE 2024 Physics - Rotational Motion Question 2 English

A small ball of mass m is suspended from the ceiling of a floor by a string of length $$\mathrm{L}$$. The ball moves along a horizontal circle with constant angular velocity $$\omega$$, as shown in the figure. The torque about the centre (O) of the horizontal circle is

A
$$\mathrm{mgL} \sin \theta$$
B
$$\mathrm{mg} \mathrm{L}$$
C
$$0$$
D
$$\mathrm{mg} \mathrm{L} \cos \theta$$
3
WB JEE 2024
MCQ (Single Correct Answer)
+1
-0.25
Change Language

A small sphere of mass m and radius r slides down the smooth surface of a large hemispherical bowl of radius R. If the sphere starts sliding from rest, the total kinetic energy of the sphere at the lowest point $$\mathrm{A}$$ of the bowl will be [given, moment of inertia of sphere $$=\frac{2}{5} \mathrm{mr}^2$$]

WB JEE 2024 Physics - Rotational Motion Question 3 English

A
$$\mathrm{mg}(\mathrm{R}-\mathrm{r})$$
B
$$\frac{7}{10} \mathrm{mg}(\mathrm{R}-\mathrm{r})$$
C
$$\frac{2}{7}$$ mg $$(\mathrm{R}-\mathrm{r})$$
D
$$\frac{10}{7} \mathrm{mg}(\mathrm{R}-\mathrm{r})$$
4
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25
Change Language

A mouse of mass m jumps on the outside edge of a rotating ceiling fan of moment of inertia I and radius R. The fractional loss of angular velocity of the fan as a result is,

A
$$\frac{m R^{2}}{I+m R^{2}}$$
B
$$\frac{I}{I+m R^{2}}$$
C
$$\frac{I-m R^{2}}{I}$$
D
$$\frac{I-m R^{2}}{I+m R^{2}}$$
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