1
WB JEE 2026
MCQ (Single Correct Answer)
+1
-0.25
Change Language

The equation of a transverse wave is $y=y_0 \sin 2 \pi\left(f t-\frac{x}{\lambda}\right)$ .If the maximum particle velocity be four times that of wave velocity then

A

$\lambda=\frac{\pi y_0}{4}$

B

$\lambda=\frac{\pi y_0}{2}$

C

$\lambda=\pi y_0$

D

$\lambda=2 \pi y_0$

2
WB JEE 2025
MCQ (Single Correct Answer)
+2
-0.5
Change Language

The equation of a stationary wave along a stretched string is given by $y=5 \sin \frac{\pi x}{3} \cos 40 \pi t$. Here $x$ and $y$ are in cm and $t$ in second. The separation between two adjacent nodes is

A
1.5 cm
B
3 cm
C
6 cm
D
14 cm
3
WB JEE 2024
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Longitudinal waves cannot

A
have a unique wave length
B
have a unique wave velocity
C
transmit energy
D
be polarized
4
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25
Change Language

The displacement of a plane progressive wave in a medium, travelling towards positive x-axis with velocity 4 m/s at t = 0 is given by $$y = 3\sin 2\pi \left( { - {x \over 3}} \right)$$. Then the expression for the displacement at a later time t = 4 sec will be

A
$$y = 3\sin 2\pi \left( { - {x-16 \over 3}} \right)$$
B
$$y = 3\sin 2\pi \left( { {-x-16 \over 3}} \right)$$
C
$$y = 3\sin 2\pi \left( { {-x+1 \over 3}} \right)$$
D
$$y = 3\sin 2\pi \left( { {-x-1 \over 3}} \right)$$

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