WB JEE 2024 | Electromagnetic Waves Question 1 | Physics

WB JEE 2024

MCQ (More than One Correct Answer)

-0

The electric field of a plane electromagnetic wave in a medium is given by

$$ \overrightarrow{\mathrm{E}}(x, y, z, t)=\mathrm{E}_0 \hat{\mathrm{n}} \mathrm{e}^{i k_o[(x+y+z)-c t]} $$

where $$\mathrm{c}$$ is the speed of light in free space. $$\overrightarrow{\mathrm{E}}$$ field is polarized in the $$x-\mathrm{z}$$ plane. The speed of wave is $$v$$ in the medium. Then

$$\hat{\mathrm{n}}=\hat{\mathrm{i}}-\hat{\mathrm{k}} ; v=\mathrm{c}$$.

$$\hat{\mathrm{n}}=\frac{\hat{\mathrm{i}}-\hat{\mathrm{k}}}{\sqrt{2}} ; v=\frac{\mathrm{c}}{\sqrt{3}}$$.

refractive index of the medium is $$\sqrt{3}$$.

$$\hat{\mathrm{n}}=\frac{\hat{\mathrm{i}}+\hat{\mathrm{k}}}{\sqrt{2}} ; v=\frac{\mathrm{c}}{\sqrt{2}}$$.

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