WB JEE 2008 | Electronic Devices Question 2 | Physics

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WB JEE 2008

MCQ (Single Correct Answer)

-0.25

The binary number 10111 is equivalent to the decimal number

WB JEE 2024

MCQ (Single Correct Answer)

-0.25

A $$2 \mathrm{~V}$$ cell is connected across the points $$\mathrm{A}$$ and $$\mathrm{B}$$ as shown in the figure. Assume that the resistance of each diode is zero in forward bias and infinity in reverse bias. The current supplied by the cell is

WB JEE 2024 Physics - Electronic Devices Question 1 English

0.5 A

0.2 A

0.1 A

0.25 A

WB JEE 2024

MCQ (Single Correct Answer)

-0.5

In the given network of AND and OR gates, output Q can be written as (assuming n even)

WB JEE 2024 Physics - Electronic Devices Question 2 English

$$\mathrm{X}_0 \mathrm{X}_1+\mathrm{X}_2 \mathrm{X}_3+\ldots \mathrm{X}_{\mathrm{n}-1} \mathrm{X}_{\mathrm{n}}$$

$$\mathrm{X}_0 \mathrm{X}_1 \ldots \mathrm{X}_{\mathrm{n}}+\mathrm{X}_1 \mathrm{X}_2 \ldots \mathrm{X}_{\mathrm{n}}+\mathrm{X}_2 \mathrm{X}_3 \ldots \mathrm{X}_{\mathrm{n}}+\mathrm{X}_{\mathrm{n}}$$

$$\mathrm{X}_0 \mathrm{X}_1 \ldots \mathrm{X}_{\mathrm{n}-1}+\mathrm{X}_{\mathrm{n}-2} \mathrm{X}_{\mathrm{n}-1}+\mathrm{X}_{\mathrm{n}}$$

$$\mathrm{X}_0 \mathrm{X}_1 \ldots \mathrm{X}_{\mathrm{n}-1}+\mathrm{X}_2 \mathrm{X}_3 \mathrm{X}_5 \ldots \mathrm{X}_{\mathrm{n}-1}+\mathrm{X}_{\mathrm{n}-2} \mathrm{X}_{\mathrm{n}-1}+\mathrm{X}_{\mathrm{n}}$$

WB JEE 2023

MCQ (Single Correct Answer)

-0.25

WB JEE 2023 Physics - Electronic Devices Question 4 English

In the given circuit, find the voltage drop $$\mathrm{V_L}$$ in the load resistance $$\mathrm{R_L}$$.

5 V

3 V

9 V

6 V

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