1
WB JEE 2022
+1
-0.25

One mole of a diatomic ideal gas undergoes a process shown in P-V diagram. The total heat given to the gas (ln 2 = 0.7) is

A
2.5 P0V0
B
3.9 P0V0
C
1.1 P0V0
D
1.4 P0V0
2
WB JEE 2022
+2
-0.5

One mole of an ideal monoatomic gas expands along the polytrope PV3 = constant from V1 to V2 at a constant pressure P1. The temperature during the process is such that molar specific heat $${C_V} = {{3R} \over 2}$$. The total heat absorbed during the process can be expressed as

A
$${P_1}{V_1}\left( {{{V_1^2} \over {V_2^2}} + 1} \right)$$
B
$${P_1}{V_1}\left( {{{V_1^2} \over {V_2^2}} - 1} \right)$$
C
$${P_1}{V_1}\left( {{{V_1^3} \over {V_2^2}} - 1} \right)$$
D
$${P_1}{V_1}\left( {{{V_1^{}} \over {V_2^2}} - 1} \right)$$
3
WB JEE 2021
+1
-0.25

In the given figure, 1 represents isobaric, 2 represents isothermal and 3 represents adiabatic processes of an ideal gas. If $$\Delta$$U1, $$\Delta$$U2 and $$\Delta$$U3 be the changes in internal energy in these processes respectively, then
A
$$\Delta$$U1 < $$\Delta$$U2 < $$\Delta$$U3
B
$$\Delta$$U1 > $$\Delta$$U2 < $$\Delta$$U3
C
$$\Delta$$U1 = $$\Delta$$U2 > $$\Delta$$U3
D
$$\Delta$$U1 > $$\Delta$$U2 > $$\Delta$$U3
4
WB JEE 2021
+1
-0.25
If pressure of real gas O2, in a container is given by $$p = {{RT} \over {2V - b}} - {a \over {4{b^2}}}$$, then the mass of the gas in the container is
A
32 g
B
16 g
C
4 g
D
64 g
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