1
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25
Change Language

$$\mathop {\lim }\limits_{x \to \infty } \left\{ {x - \root n \of {(x - {a_1})(x - {a_2})\,...\,(x - {a_n})} } \right\}$$ where $${a_1},{a_2},\,...,\,{a_n}$$ are positive rational numbers. The limit

A
does not exist
B
is $${{{a_1} + {a_2}\, + \,...\,{a_n}} \over n}$$
C
is $$\root n \of {{a_1}{a_2}\,...\,{a_n}} $$
D
is $${n \over {{a_1} + {a_2}\, + \,...\,{a_n}}}$$
2
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Let $$f:[1,3] \to R$$ be continuous and be derivable in (1, 3) and $$f'(x) = {[f(x)]^2} + 4\forall x \in (1,3)$$. Then

A
$$f(3) - f(1) = 5$$ holds
B
$$f(3) - f(1) = 5$$ does not hold
C
$$f(3) - f(1) = 3$$ holds
D
$$f(3) - f(1) = 4$$ holds
3
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25
Change Language

f(x) is a differentiable function and given $$f'(2) = 6$$ and $$f'(1) = 4$$, then $$L = \mathop {\lim }\limits_{h \to 0} {{f(2 + 2h + {h^2}) - f(2)} \over {f(1 + h - {h^2}) - f(1)}}$$

A
does not exist
B
equal to $$-3$$
C
equal to 3
D
equal to 3/2
4
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Let $$f(x) = \left\{ {\matrix{ {x + 1,} & { - 1 \le x \le 0} \cr { - x,} & {0 < x \le 1} \cr } } \right.$$

A
f(x) is discontinuous in [$$-1,1$$] and so has no maximum value or minimum value in [$$-1,1$$].
B
f(x) is continuous in [$$-1,1$$] and so has maximum value and minimum value.
C
f(x) is discontinuous in [$$-1,1$$] but still has the maximum and minimum value.
D
f(x) is bounded in [$$-1,1$$] and does not attain maximum or minimum value.
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