1
WB JEE 2022
MCQ (Single Correct Answer)
+1
-0.25
Change Language

$$\mathop {\lim }\limits_{x \to 0} \left( {{1 \over x}\ln \sqrt {{{1 + x} \over {1 - x}}} } \right)$$ is

A
$${1 \over 2}$$
B
0
C
1
D
does not exist
2
WB JEE 2022
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Let f : [a, b] $$\to$$ R be continuous in [a, b], differentiable in (a, b) and f(a) = 0 = f(b). Then

A
there exists at least one point $$c \in (a,b)$$ for which $$f'(c) = f(c)$$
B
$$f'(x) = f(x)$$ does not hold at any point of (a, b)
C
at every point of $$(a,b),f'(x) > f(x)$$
D
at every point of $$(a,b),f'(x) < f(x)$$
3
WB JEE 2022
MCQ (Single Correct Answer)
+2
-0.5
Change Language

$$\mathop {\lim }\limits_{x \to \infty } \left( {{{{x^2} + 1} \over {x + 1}} - ax - b} \right),(a,b \in R)$$ = 0. Then

A
a = 0, b = 1
B
a = 1, b = $$-$$1
C
a = $$-$$1, b = 1
D
a = 0, b = 0
4
WB JEE 2021
MCQ (Single Correct Answer)
+1
-0.25
Change Language
If $$I = \mathop {\lim }\limits_{x \to 0} sin\left( {{{{e^x} - x - 1 - {{{x^2}} \over 2}} \over {{x^2}}}} \right)$$, then limit
A
does not exist
B
exists and equals 1
C
exists and equals 0
D
exists and equals $${1 \over 2}$$
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