1
TS EAMCET 2023 (Online) 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let a chord $A B$ subtend an angle of $60^{\circ}$ at the centre $C(2,3)$ of a circle $S$. If the equation of $A B$ is $x+y+1=0$, then the equation of the circle $S$ is

A

$x^2+y^2-4 x-6 y+11=0$

B

$x^2+y^2-4 x-6 y+37=0$

C

$x^2+y^2-4 x-6 y-11=0$

D

$x^2+y^2-4 x-6 y-37=0$

2
TS EAMCET 2023 (Online) 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let 6,8 be the $X$ and $Y$-intercepts made by the circle $S \equiv x^2+y^2+2 g x+2 f y+c=0$, respectively. If $g x+f y+1=0$ is a line passing through the point $(1,-1)$, then the radius of the circle $S=0$ is

A

$\sqrt{41}$

B

13

C

$\sqrt{26}$

D

5

3
TS EAMCET 2023 (Online) 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $(3,1)$ and $(-2,4)$ are points on a circle $S$ whose centre lies on the line $x-y+1=0$, then the parametric equations of $S$ are

A

$x=-1+\sqrt{17} \cos \theta, y=\sqrt{17} \sin \theta$

B

$x=2+\sqrt{13} \cos \theta, y=1+\sqrt{13} \sin \theta$

C

$x=\sqrt{26} \cos \theta, y=-1+\sqrt{26} \sin \theta$

D

$x=-1+\sqrt{19} \cos \theta, y=2+\sqrt{19} \sin \theta$

4
TS EAMCET 2023 (Online) 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let $S \equiv x^2+y^2-8 x+10 y+5=0$ be a circle. Let $P(1,1)$ and $Q(1,-1)$ be two points. Then, the point of intersection of the polar of $P$ with respect to $S=0$ and the chord with $Q$ as mid-point to $S=0$ is

A

$(2,2)$

B

$(11,13 / 2)$

C

$(-4,-1)$

D

$(5,7 / 2)$

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