1
TS EAMCET 2020 (Online) 14th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $y(x)=\tan ^{-1}\left(\frac{\sqrt{1+a^2 x^2}-1}{a x}\right)$ and $\left(1+a^2 x^2\right) y^{\prime \prime}+g(x) y^{\prime}=0$ then, the sum of the roots of the equation $1+a^2 x^2+g(x)=0$ is

A

$2 a$

B

$-2 a^2$

C

2

D

-2

2
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Match the functions of List-I with derivates given in List-II

$$
\text { List-I }
$$
$$
\text { List-II }
$$
A. $$
\sec ^{-1} x
$$
I. $$
\frac{1}{1-x^2}, x \in(-1,1)
$$
B. $$
\tanh ^{-1} x
$$
II. $$
\frac{-1}{|x| \sqrt{x^2+1}}, x \neq 0
$$
C. $$
\operatorname{coth}^{-1} x
$$
III. $$
\frac{1}{|x| \sqrt{x^2-1}},|x|>1
$$
D. $$
\operatorname{cosech}^{-1} x
$$
IV. $$
\frac{1}{1-x^2}, x \in \mathbf{R}-[-1,1]
$$
V. $$
\frac{-1}{|x| \sqrt{1-x^2}},|x|<1, x \neq 0
$$
A
A B C D
V II I III
B
A B C D
I III V II
C
A B C D
III I II V
D
A B C D
III I IV II
3
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $f(x)=\frac{x-1}{e^x}$, then $f^{\prime}(0)+f^{\prime \prime}(0)=$

A

0

B

1

C

-1

D

2

4
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \begin{aligned} & \text { If }\left(\frac{d y}{d x}\right)=\frac{1}{\left(\frac{d x}{d y}\right)} \text { and } \frac{d^2 x}{d y^2}\left(\frac{d y}{d x}\right)^3+\frac{d^2 y}{d x^2}=k \text {, then } \\ & e^{k f(x)}-k f(x)= \end{aligned} $$

A

1

B

0

C

$1 / 2$

D

2

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