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TG EAPCET 2024 (Online) 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $x=\frac{9 t^2}{1+t^4}$ and $y=\frac{16 t^2}{1-t^4}$ then $\frac{d y}{d x}=$

A
$\frac{16}{9}\left(\frac{1-t^4}{1+t^4}\right)^3$
B
$\frac{16}{9} \frac{\left(1-t^4\right)}{\left(1+t^4\right)}$
C
$\frac{9}{16} \frac{\left(1-t^4\right)}{\left(1+t^4\right)}$
D
$\frac{16}{9}\left(\frac{1+t^4}{1-t^4}\right)^3$
2
TG EAPCET 2024 (Online) 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
If $y=\sin a x+\cos b x$, then $y^{\prime \prime}+b^2 y=$
A
$\left(b^2-a^2\right) \sin a x$
B
$\left(b^2-a^2\right) \cos b x$
C
$\left(a^2-b^2\right) \tan a x$
D
$\left(b^2-a^2\right) \cot b x$
3
TG EAPCET 2024 (Online) 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
A particle moving from a fixed point on a straight line travels a distance $S$ metres in $t \mathrm{sec}$. If $S=t^3-t^2-t+3$, then the distance (in mts) travelled by the particle when it comes to rest, is
A
5
B
4
C
2
D
3
4
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\sec \left(\log _2 y^2\right)=\operatorname{cosec}\left(\log _2 x^2\right)$, then $\frac{d y}{d x}=$

A
$\frac{x}{y}$
B
$\frac{y}{x}$
C
$-\frac{y}{x}$
D
$-\frac{x}{y}$
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