TS EAMCET 2022 (Online) 18th July Morning Shift | Chemical Kinetics Question 24 | Chemistry

If the definition of the temperature coefficient of the reaction holds good for a reaction between $27^{\circ} \mathrm{C}$ and $37^{\circ} \mathrm{C}$, the activation energy for the reaction in $\mathrm{kJ} \mathrm{mol}^{-1}$ is

102

53.5

$\infty$

141.5

TS EAMCET 2020 (Online) 14th September Morning Shift

MCQ (Single Correct Answer)

-0

The half-life of a first order reaction varies with temperature according to

$\ln \left(t_{1 / 2}\right) \propto \frac{1}{T}$

$\operatorname{In}\left(t_{1 / 2}\right) \propto T$

$\left(t_{1 / 2}\right) \propto \frac{1}{T^2}$

$\left(t_{1 / 2}\right) \propto T^2$

TS EAMCET 2020 (Online) 11th September Evening Shift

MCQ (Single Correct Answer)

-0

What is the unit for the zero order rate constant?

$\mathrm{L}^{-1} \mathrm{~mol} \mathrm{~s}^{-1}$

$\mathrm{L} \mathrm{mol} \mathrm{s}^{-1}$

$\mathrm{L} \mathrm{mol}^{-1} \mathrm{~s}^{-1}$

$\mathrm{L}^2 \mathrm{~mol}^{-2} \mathrm{~s}^{-1}$

TS EAMCET 2020 (Online) 11th September Morning Shift

MCQ (Single Correct Answer)

-0

For a first order reaction ( $A \rightarrow B$ ), the temperature ( $T$ ) dependent rate constant $(k)$ in $\mathrm{s}^{-1}$ was found to follow the equation $: \log k=\left(-\frac{20}{T}\right)+4$. The activation energy ( $E_a$ ) and pre-exponential factor ( $A$ ) respectively, are

$46.06 \mathrm{cal} \mathrm{mol}^{-1}$ and $10^{-4} \mathrm{~s}^{-1}$

$92.12 \mathrm{cal} \mathrm{mol}^{-1}$ and $10^4 \mathrm{~s}^{-1}$

$46.06 \mathrm{cal} \mathrm{mol}^{-1}$ and $10^4 \mathrm{~s}^{-1}$

$9.212 \mathrm{cal} \mathrm{mol}^{-1}$ and $10^{-4} \mathrm{~s}^{-1}$

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