TS EAMCET 2020 (Online) 11th September Morning Shift | Chemical Kinetics Question 27 | Chemistry

For a first order reaction ( $A \rightarrow B$ ), the temperature ( $T$ ) dependent rate constant $(k)$ in $\mathrm{s}^{-1}$ was found to follow the equation $: \log k=\left(-\frac{20}{T}\right)+4$. The activation energy ( $E_a$ ) and pre-exponential factor ( $A$ ) respectively, are

$46.06 \mathrm{cal} \mathrm{mol}^{-1}$ and $10^{-4} \mathrm{~s}^{-1}$

$92.12 \mathrm{cal} \mathrm{mol}^{-1}$ and $10^4 \mathrm{~s}^{-1}$

$46.06 \mathrm{cal} \mathrm{mol}^{-1}$ and $10^4 \mathrm{~s}^{-1}$

$9.212 \mathrm{cal} \mathrm{mol}^{-1}$ and $10^{-4} \mathrm{~s}^{-1}$

TS EAMCET 2020 (Online) 10th September Evening Shift

MCQ (Single Correct Answer)

-0

The specific rate constant of decomposition of a compound is given by $\ln k=5.0-\frac{12000}{T}$. The activation energy of decomposition for this compound at 300 K is

$24 \mathrm{kcal} \mathrm{mol}^{-1}$

$12 \mathrm{kcal} \mathrm{mol}^{-1}$

$24 \mathrm{cal} \mathrm{mol}^{-1}$

$12 \mathrm{cal} \mathrm{mol}^{-1}$

TS EAMCET 2020 (Online) 10th September Morning Shift

MCQ (Single Correct Answer)

-0

For a zero order reaction, the plot of concentration of reactant vs time is (Hint: Consider the intercept on the concentration axis)

linear with +ve slope and non zero +ve intercept

linear with -ve slope and non zero +ve intercept

linear with -ve slope and zero intercept

linear with $+v e$ slope and zero intercept

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