If $(\alpha, \beta)$ is the centre of the circle which passes through the point $(1,-1)$ and cuts the circles

$$ x^2+y^2+2 x-3 y-5=0, x^2+y^2-3 x+2 y+1=0 $$

orthogonally, then $\alpha-5 \beta=$

The centre of the circle touching the circles $x^2+y^2-4 x-6 y-12=0$

$x^2+y^2+6 x+18 y+26=0$ at their point of contact and passing through the point $(1,-1)$ is

The equation of the locus of a point, which is at a distance of 5 units from a fixed point $(1,4)$ and also from a fixed line $2 x+3 y-1=0$ is

If the equation of the circumcircle of the triangle formed by the lines $L_1 \equiv x+y=0$,

$L_2 \equiv 2 x+y-1=0, L_3 \equiv x-3 y+2=0$ is $\lambda_1 L_1 L_2+\lambda_2 L_2 L_3+\lambda_3 L_3 L_1=0$, then $\frac{7 \lambda_1}{\lambda_2}+\frac{\lambda_3}{\lambda_1}=$