1
TG EAPCET 2025 (Online) 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$1+\cos x+\cos ^2 x+\cos ^3 x+\ldots$ to $\infty=4+2 \sqrt{3}$, then $x=$

A

$\frac{n \pi}{6}$

B

$(4 n \pm 1) \frac{\pi}{3}$

C

$(12 n \pm 1) \frac{\pi}{6}$

D

$(3 n \pm 1) \frac{\pi}{3}$

2
TG EAPCET 2025 (Online) 2nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0
$\alpha, \beta$ are the roots of the equation $\sin ^2 x+b \sin x+c=0$. If $\alpha+\beta=\frac{\pi}{2}$, then $b^2-1=$
A
$C$
B
$2 c$
C
$C^2$
D
$4 c^2$
3
TG EAPCET 2025 (Online) 2nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The general solution of the equation $\sqrt{6-5 \cos x+7 \sin ^2 x}-\cos x=0$ also satisfies the equation

A

$\tan x+\cot x=2$

B

$\cot x+\operatorname{cosec} x=1$

C

$\tan x+\sec x=1$

D

$\sec x+\operatorname{cosec} x=2$

4
TG EAPCET 2024 (Online) 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
Suppose, $\theta_{1}$ and $\theta_{2}$ are such that $\left(\theta_{1}-\theta_{2}\right)$ lies in 3rd or 4th quadrant. If $\sin \theta_{1}+\sin \theta_{2}=-\frac{21}{65}$ and $\cos \theta_{1}+\cos \theta_{2}=-\frac{27}{65}$, then $\cos \left(\frac{\theta_{1}-\theta_{2}}{2}\right)=$
A
$\frac{3}{\sqrt{150}}$
B
$\frac{3}{\sqrt{130}}$
C
$-\frac{3}{\sqrt{130}}$
D
$-\frac{3}{\sqrt{150}}$

TS EAMCET Subjects

Browse all chapters by subject