1
TG EAPCET 2025 (Online) 2nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int_0^2 \sqrt{(x+3)(2-x)} d x= $$

A

$\frac{25}{8} \cos ^{-1}\left(\frac{1}{5}\right)-\frac{\sqrt{6}}{4}$

B

$\frac{25}{8} \sin ^{-1}\left(\frac{1}{5}\right)-\frac{\sqrt{6}}{4}$

C

$\frac{\pi}{2}$

D

$\pi$

2
TG EAPCET 2025 (Online) 2nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int_0^{\pi / 4} x^2 \sin 2 x d x $$

A

$\frac{\pi^2-2}{8}$

B

$\frac{\pi(\pi-2)}{8}$

C

$\frac{\pi-2}{8}$

D

$\frac{\pi+2}{8}$

3
TG EAPCET 2025 (Online) 2nd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int_{-2 \pi}^{2 \pi} \sin ^4 x \cos ^6 x d x= $$

A

$\frac{3 \pi}{128}$

B

$\frac{9 \pi}{32}$

C

$\frac{9 \pi}{64}$

D

$\frac{3 \pi}{64}$

4
TG EAPCET 2024 (Online) 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
$\int_{\frac{\pi}{5}}^{\frac{3 \pi}{10}} \frac{d x}{\sec ^{2} x+\left(\tan ^{2024} x-1\right)\left(\sec ^{2} x-1\right)}=$
A
$\frac{\pi}{20}$
B
$\frac{2 \pi}{5}$
C
$\frac{3 \pi}{20}$
D
$\frac{3 \pi}{5}$

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