1
TG EAPCET 2025 (Online) 3rd May Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int \frac{\log x}{(1+x)^3} d x= $$

A

$\frac{1}{2}\left[\frac{1}{1+x}+\frac{\log x}{(1+x)^2}-\log \left(x^2+x\right)\right]+C$

B

$\frac{1}{2}\left[\frac{1}{1+x}-\frac{\log x}{(1+x)}-\log \left(1+x^2\right)\right]+C$

C

$\frac{1}{2}\left[\frac{1}{1+x}+\frac{\log x}{(1+x)^2}-\log \left(1+x^2\right)\right]+C$

D

$\frac{1}{2}\left[\frac{1}{1+x}-\frac{\log x}{(1+x)^2}+\log \left(\frac{x}{1+x}\right)\right]+C$

2
TG EAPCET 2025 (Online) 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\frac{x^2-3}{(x+2)\left(x^2+1\right)}=\frac{A}{x+2}+\frac{B x+C}{\left(x^2+1\right)}$, then $3 A+2 B-C=$

A

$\frac{8}{5}$

B

$\frac{16}{5}$

C

$\frac{3}{5}$

D

$\frac{19}{5}$

3
TG EAPCET 2025 (Online) 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int\left(\frac{1}{x^2}+\frac{\sin ^3 x+\cos ^3 x}{\sin ^2 x \cos ^2 x}\right) d x= $$

A

$\frac{(\sin x-\cos x) x-\sin x \cos x}{x \sin x \cos x}+C$

B

$-\frac{1}{x}+\frac{\sin x+\cos x}{\cos x-\sin x}+c$

C

$-\frac{1}{x}+\frac{\sin x-\cos x}{\sin ^2 x \cos ^2 x}+C$

D

$\frac{(\sin x-\cos x) x-\sin x-\cos x}{x(\sin x+\cos x)}+C$

4
TG EAPCET 2025 (Online) 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $I_n=\int \frac{1}{\left(x^2+1\right)^n} d x$, then $2 n I_{n+1}-(2 n-1) I_n=$

A

$\frac{\left(x^2+1\right)^n}{x}+C$

B

$\frac{x}{\left(x^2+1\right)^n}+C$

C

$x\left(x^2+1\right)^{n-1}+C$

D

$\frac{x}{\left(x^2+1\right)^{n-1}}+C$

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