1
TG EAPCET 2024 (Online) 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
$\int\left(\frac{\left(\sin ^4 x+2 \cos ^2 x-1\right) \cos x}{(1+\sin x)^6}\right) d x=$
A
$\frac{\sin ^6 x}{6(1+\sin x)^6}+c$
B
$-\frac{\sin ^6 x}{6(1+\sin x)^6}+c$
C
$\frac{\cos ^6 x}{6(1+\sin x)^6}+c$
D
$-\frac{\cos ^6 x}{6(1+\sin x)^6}+c$
2
TG EAPCET 2024 (Online) 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
$\int(\log x)^3 d x=$
A
$(\log x)^3-3(\log x)^2+6 \log x-6+c$
B
$x\left[(\log x)^3-3(\log x)^2+6(\log x)-6\right]+c$
C
$(x \log x)^3-3 x(\log x)^2+6 x(\log x)-6+c$
D
$\frac{1}{x}\left[(\log x)^3-3(\log x)^2+6 \log x-6\right]+c$
3
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
If $\frac{3 x^4-2 x^2+1}{(x-2)^4}=A+\frac{B}{x-2}+\frac{C}{(x-2)^2}$ $+\frac{D}{(x-2)^3}+\frac{E}{(x-2)^4}$, then $2 A+3 B-C-D+E=$
A
0
B
1
C
-11
D
-39
4
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
$\int e^{-2 x}\left(\tan 2 x-2 \sec ^2 2 x \tan 2 x\right) d x=$
A
$e^{-2 x} \tan 2 x+c$
B
$-\frac{e^{-2 x}}{2}\left[\sec ^2 2 x+\tan 2 x\right]+c$
C
$-\frac{e^{-2 x}}{2}\left[\tan 2 x-\sec ^2 2 x\right]+c$
D
$e^{-2 x} \sec ^2 2 x+c$
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