1
TG EAPCET 2024 (Online) 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
$\int\left(\frac{4 \tan ^4 x+3 \tan ^2 x-1}{\tan ^2 x+4}\right) d x=$
A
$4 \tan x-\frac{17}{4} \tan ^{-1}\left(\frac{\tan x}{4}\right)+c$
B
$4 \tan x-\frac{17}{4} \tan ^{-1}\left(\frac{\tan x}{2}\right)+c$
C
$4 \tan x-\frac{17}{2} \tan ^{-1}\left(\frac{\tan x}{2}\right)+c$
D
$2 \tan x-\frac{17}{2} \tan ^{-1}\left(\frac{\tan x}{2}\right)+c$
2
TG EAPCET 2024 (Online) 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
$\int\left(\frac{\left(\sin ^4 x+2 \cos ^2 x-1\right) \cos x}{(1+\sin x)^6}\right) d x=$
A
$\frac{\sin ^6 x}{6(1+\sin x)^6}+c$
B
$-\frac{\sin ^6 x}{6(1+\sin x)^6}+c$
C
$\frac{\cos ^6 x}{6(1+\sin x)^6}+c$
D
$-\frac{\cos ^6 x}{6(1+\sin x)^6}+c$
3
TG EAPCET 2024 (Online) 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
$\int(\log x)^3 d x=$
A
$(\log x)^3-3(\log x)^2+6 \log x-6+c$
B
$x\left[(\log x)^3-3(\log x)^2+6(\log x)-6\right]+c$
C
$(x \log x)^3-3 x(\log x)^2+6 x(\log x)-6+c$
D
$\frac{1}{x}\left[(\log x)^3-3(\log x)^2+6 \log x-6\right]+c$
4
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
If $\frac{3 x^4-2 x^2+1}{(x-2)^4}=A+\frac{B}{x-2}+\frac{C}{(x-2)^2}$ $+\frac{D}{(x-2)^3}+\frac{E}{(x-2)^4}$, then $2 A+3 B-C-D+E=$
A
0
B
1
C
-11
D
-39
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