WB JEE 2016 | Motion Question 9 | Physics

WB JEE 2016

MCQ (More than One Correct Answer)

-0

A train moves from rest with acceleration $$\alpha$$ and in time t₁ covers a distance x. It then decelerates to rest at constant retardation $$\beta$$ for distance y in time t₂. Then,

$${x \over y} = {\beta \over \alpha }$$

$${\beta \over \alpha } = {{{t_1}} \over {{t_2}}}$$

x = y

$${x \over y} = {{\beta {t_1}} \over {\alpha {t_2}}}$$

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