WB JEE 2021 | Ionic Equilibrium Question 15 | Chemistry

WB JEE 2021

MCQ (Single Correct Answer)

-0.25

A saturated solution of BaSO₄ at 25$$^\circ$$C is 4 $$\times$$ 10^$$-$$5 M. The solubility of BaSO₄ in 0.1 M Na₂SO₄ at this temperature will be

1.6 $$\times$$ 10^$$-$$9 M

1.6 $$\times$$ 10^$$-$$8 M

4 $$\times$$ 10^$$-$$6 M

4 $$\times$$ 10^$$-$$4 M

WB JEE 2020

MCQ (Single Correct Answer)

-0.5

A solution is saturated with SrCO₃ and SrF₂. The $$[CO_3^{2 - }]$$ is found to be 1.2 $$ \times $$ 10^-3 M. The concentration of F^- in the solution would be

Given : K_sp(SrCO₃) = 7.0 $$ \times $$ 10^-10,

K_sp(SrF₂) = 7.9 $$ \times $$ 10^-10

$$3.7 \times {10^{ - 6}}$$ M

$$3.2 \times {10^{ - 3}}$$ M

$$5.1 \times {10^{ - 7}}$$ M

$$3.7 \times {10^{ - 2}}$$ M

WB JEE 2019

MCQ (Single Correct Answer)

-0.33

Which of the following mixtures will have the lowest pH at 298 K?

10 mL 0.05 N CH₃COOH + 5 mL 0.1 N NH₄OH

5 mL 0.2 N NH₄Cl + 5 mL 0.2 N NH₄OH

5 mL 0.1 N CH₃COOH + 10 mL 0.05 N CH₃COONa

5 mL 0.1 N CH₃COOH + 5 mL 0.1 N NaOH

WB JEE 2017

MCQ (Single Correct Answer)

-0.25

Dissolving NaCN in de-ionised water will result in a solution having

pH < 7

pH = 7

pOH = 7

pH > 7

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