1
MHT CET 2025 22nd April Morning Shift
MCQ (Single Correct Answer)
+1
-0

Half life of a first order reaction is 20 minutes. The time taken to reduce the initial concentration of reactant to $(1 / 10)^{\text {th }}$ is _________

A
46.60 min
B
66.46 min
C
79.68 min
D
88.00 min
2
MHT CET 2025 22nd April Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $\mathrm{E}^{\cdot}\left(\mathrm{Mg}_{(\mathrm{aq})}^{+2} \mid \mathrm{Mg}_{(\mathrm{s})}\right)=-2.37 \mathrm{~V}$. What is potential for $\mathrm{Mg}_{(\mathrm{s})} \longrightarrow \mathrm{Mg}^{+2}(0.01 \mathrm{M})+2 \mathrm{e}^{-}$at 298 K ?

A
+2.3108 V
B
-2.3108 V
C
+2.4292 V
D
-2.4292 V
3
MHT CET 2025 22nd April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $y=y(x)$ and $\left(\frac{2+\sin x}{y+1}\right) \frac{\mathrm{d} y}{\mathrm{~d} x}=-\cos x, y(0)=1$, then $y\left(\frac{\pi}{2}\right)=$

A
$\frac{1}{3}$
B
$\frac{2}{3}$
C
$-\frac{1}{3}$
D
1
4
MHT CET 2025 22nd April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $A=\left[\begin{array}{cc}1 & \cot \frac{\theta}{2} \\ -\cot \frac{\theta}{2} & 1\end{array}\right]$ then $A^{-1}=$

A
$\operatorname{cosec}^2 \frac{\theta}{2} \mathrm{~A}^{\mathrm{T}}$
B
$\frac{-\sin ^2 \theta}{2} A^T$
C
$\left(\frac{1+\cos \theta}{2}\right) A^T$
D
$\left(\frac{1-\cos \theta}{2}\right) A^T$
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