MHT CET 2025 22nd April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

In a triangle ABC with usual notations if, $\tan \left(\frac{\mathrm{B}-\mathrm{C}}{2}\right)=x \cot \frac{\mathrm{~A}}{2}$, then $x=$

$\frac{c-a}{c+a}$

$\frac{a-b}{a+b}$

$\frac{\mathrm{b}-\mathrm{c}}{\mathrm{b}+\mathrm{c}}$

$\frac{a+b}{a-b}$

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

A coin is tossed until one head appears or a tail appears 4 times in succession. The probability distribution of the number of tosses is

$$ \begin{array}{|l|c|c|c|c|} \hline \mathrm{X} & 1 & 2 & 3 & 4 \\ \hline \mathrm{P}(\mathrm{X}=x) & \frac{1}{8} & \frac{1}{8} & \frac{1}{2} & \frac{1}{4} \\ \hline \end{array} $$

$$ \begin{array}{|l|c|c|c|c|} \hline \mathrm{X} & 1 & 2 & 3 & 4 \\ \hline \mathrm{P}(\mathrm{X}=x) & \frac{1}{4} & \frac{1}{2} & \frac{1}{8} & \frac{1}{8} \\ \hline \end{array} $$

$$ \begin{array}{|l|c|c|c|c|} \hline \mathrm{X} & 1 & 2 & 3 & 4 \\ \hline \mathrm{P}(\mathrm{X}=x) & \frac{1}{8} & \frac{1}{4} & \frac{1}{8} & \frac{1}{2} \\ \hline \end{array} $$

$$ \begin{array}{|l|c|c|c|c|} \hline \mathrm{X} & 1 & 2 & 3 & 4 \\ \hline \mathrm{P}(\mathrm{X}=x) & \frac{1}{2} & \frac{1}{4} & \frac{1}{8} & \frac{1}{8} \\ \hline \end{array} $$

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

The degree of the differential equation $\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}+3\left(\frac{\mathrm{~d} y}{\mathrm{~d} x}\right)^2=x^2 \log \left(\frac{\mathrm{~d}^2 y}{\mathrm{~d} x^2}\right)$ is

Not defined

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

If the sum of the squares of the distances of a point $\mathrm{P}(x, y, z)$ from the three co-ordinate axes is 324 , then the distance of point P from the origin is ….

162

$9 \sqrt{2}$

324

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