MHT CET 2025 22nd April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

Nitric oxide reacts with $\mathrm{H}_2$ according to reaction. $2 \mathrm{NO}_{(\mathrm{g})}+2 \mathrm{H}_{2(\mathrm{~g})} \rightarrow \mathrm{N}_{2(\mathrm{~g})}+2 \mathrm{H}_2 \mathrm{O}_{(\mathrm{g})}$, identify correct relation for disappearance of reactant and appearance of product.

$\frac{1}{2} \frac{\mathrm{~d}[\mathrm{NO}]}{\mathrm{dt}}=-\frac{\mathrm{d}\left[\mathrm{H}_2\right]}{\mathrm{dt}}$

$\frac{\mathrm{d}\left[\mathrm{N}_2\right]}{\mathrm{dt}}=\frac{1}{2} \frac{\mathrm{~d}\left[\mathrm{H}_2 \mathrm{O}\right]}{\mathrm{dt}}$

$-\frac{\mathrm{d}\left[\mathrm{N}_2\right]}{\mathrm{dt}}=\frac{1}{2} \frac{\mathrm{~d}\left[\mathrm{H}_2 \mathrm{O}\right]}{\mathrm{dt}}$

$\frac{\mathrm{d}\left[\mathrm{H}_2\right]}{\mathrm{dt}}=-\frac{1}{2} \frac{\mathrm{~d}\left[\mathrm{~N}_2\right]}{\mathrm{dt}}$

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

The solubility of sparingly soluble salt $\mathrm{AX}_2$ is $1 \times 10^{-4} \mathrm{~mol} \mathrm{dm}^{-3}$ at 298 K . Calculate its solubility product.

$2 \times 10^{-12}$

$4 \times 10^{-12}$

$2 \times 10^{-10}$

$4 \times 10^{-10}$

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

Which of the following is used as Green solvent?

Supercritical $\mathrm{CO}_2$

$\mathrm{CHCl}_3$

$\quad \mathrm{CH}_2 \mathrm{Cl}_2$

$\mathrm{CCl}_4$

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

What is vapour density of $\mathrm{O}_2$ gas?

22.4

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