1
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

$\int \frac{x^2-4}{x^4+9 x^2+16} \mathrm{dx}=\tan ^{-1}(\mathrm{f}(x))+\mathrm{c}$ (where c is a constant of integration), then value of $f(2)$ is

A
1
B
2
C
3
D
4
2
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $\overline{\mathrm{a}}=\hat{\mathrm{i}}-2 \hat{\mathrm{j}}+3 \hat{\mathrm{k}}$ and $\overline{\mathrm{b}}=2 \hat{i}+3 \hat{\mathrm{j}}-\hat{\mathrm{k}}$ are two vectors, then the angle between the vectors $3 \overline{\mathrm{a}}+5 \overline{\mathrm{~b}}$ and $5 \overline{\mathrm{a}}+3 \overline{\mathrm{~b}}$ is

A
$\cos ^{-1}\left(\frac{10}{19}\right)$
B
$\cos ^{-1}\left(\frac{11}{19}\right)$
C
$\cos ^{-1}\left(\frac{13}{19}\right)$
D
$\cos ^{-1}\left(\frac{14}{19}\right)$
3
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

Let $A=\left[\begin{array}{cc}1 & 2 \\ -1 & 4\end{array}\right]$ and $A^{-1}=\alpha \mathrm{I}+\beta \mathrm{A}, \alpha, \beta \in \mathbb{R}$, I is the identity matrix of order 2 , then $4(\alpha-\beta)$ is

A
$\frac{8}{3}$
B
4
C
2
D
5
4
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

$$\lim _\limits{y \rightarrow 0} \frac{\sqrt{1+\sqrt{1+y^4}}-\sqrt{2}}{y^4}=$$

A
 $0$
B
$\frac{1}{2 \sqrt{2}}$
C
$\frac{1}{4 \sqrt{2}}$
D
$\frac{1}{2 \sqrt{2}(\sqrt{2}+1)}$
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