1
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In Young's double slit experiment, the fifth maximum with wavelength '$$\lambda_1$$' is at a distance '$$y_1$$' and the same maximum with wavelength '$$\lambda_2$$' is at a distance '$$y_2$$' measured from the central bright band. Then $$\frac{y_1}{y_2}$$ is equal to [D and $$d$$ are constant]

A
$$\frac{\lambda_1}{\lambda_2}$$
B
$$\frac{\lambda_2}{\lambda_1}$$
C
$$\frac{\lambda_1^2}{\lambda_2^2}$$
D
$$\frac{\lambda_2^2}{\lambda_1^2}$$
2
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Bohr model is applied to a particle of mass '$$\mathrm{m}$$' and charge '$$\mathrm{q}$$' moving in a plane under the influence of a transverse magnetic field '$$B$$'. The energy of the charged particle in the $$\mathrm{n}^{\text {th }}$$ leve will be $$[\mathrm{h}=$$ Planck's constant $$]$$

A
$$\frac{n h q B}{4 \pi \mathrm{m}}$$
B
$$\frac{n h q B}{2 \pi m}$$
C
$$\frac{\text { nhqB }}{\pi \mathrm{m}}$$
D
$$\frac{2 \mathrm{nhqB}}{\pi \mathrm{m}}$$
3
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A rectangular block of mass '$$\mathrm{m}$$' and crosssectional area A, floats on a liquid of density '$$\rho$$'. It is given a small vertical displacement from equilibrium, it starts oscillating with frequency '$$n$$' equal to ( $$g=$$ acceleration due to gravity)

A
$$\frac{1}{2 \pi} \sqrt{\frac{\mathrm{Apg}}{\mathrm{m}}}$$
B
$$2 \pi \sqrt{\frac{\mathrm{Apg}}{\mathrm{m}}}$$
C
$$\frac{1}{2 \pi} \sqrt{\frac{\mathrm{m}}{\mathrm{Apg}}}$$
D
$$2 \pi \sqrt{\frac{\mathrm{m}}{\mathrm{Apg}}}$$
4
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two spherical conductors of capacities $$3 \mu \mathrm{F}$$ and $$2 \mu \mathrm{F}$$ are charged to same potential having radii $$3 \mathrm{~cm}$$ and $$2 \mathrm{~cm}$$ respectively. If '$$\sigma_1$$' and '$$\sigma_2$$' represent surface density of charge on respective conductors then $$\frac{\sigma_1}{\sigma_2}$$ is

A
$$\frac{1}{3}$$
B
$$\frac{1}{2}$$
C
$$\frac{2}{3}$$
D
$$\frac{3}{4}$$
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