1
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A liquid drop of radius '$$R$$' is broken into '$$n$$' identical small droplets. The work done is [T = surface tension of the liquid]

A
$$4 \pi \mathrm{R}^2\left(\mathrm{n}^{\frac{2}{3}}-1\right) \mathrm{T}$$
B
$$4 \pi R^2\left(n^{\frac{1}{3}}-1\right) T$$
C
$$4 \pi R^2\left(1-n^{\frac{1}{3}}\right) T$$
D
$$4 \pi \mathrm{R}^2\left(1-\mathrm{n}^{\frac{2}{3}}\right) \mathrm{T}$$
2
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

For a gas, $$\frac{\mathrm{R}}{\mathrm{C}_{\mathrm{v}}}=0 \cdot 4$$, where $$\mathrm{R}$$ is universal gas constant and $$\mathrm{C}_{\mathrm{v}}$$ is molar specific heat at constant volume. The gas is made up of molecules which are

A
rigid diatomic
B
monoatomic
C
non-rigid diatomic
D
polyatomic
3
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two bodies $$\mathrm{A}$$ and $$\mathrm{B}$$ at temperatures '$$\mathrm{T}_1$$' $$\mathrm{K}$$ and '$$\mathrm{T}_2$$' $$\mathrm{K}$$ respectively have the same dimensions. Their emissivities are in the ratio $$1: 3$$. If they radiate the same amount of heat per unit area per unit time, then the ratio of their temperatures $$\left(\mathrm{T}_1: \mathrm{T}_2\right)$$ is

A
$$1: 3$$
B
$$3^{1 / 4}: 1$$
C
$$9^{1 / 4}: 1$$
D
$$81: 1$$
4
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In a conical pendulum the bob of mass '$$\mathrm{m}$$' moves in a horizontal circle of radius '$$r$$' with uniform speed '$$\mathrm{V}$$'. The string of length '$$\mathrm{L}$$' describes a cone of semi vertical angle '$$\theta$$'. The centripetal force acting on the bob is ( $$\mathrm{g}=$$ acceleration due to gravity)

A
$$\frac{\mathrm{mgr}}{\sqrt{\mathrm{L}^2-\mathrm{r}^2}}$$
B
$$\frac{\mathrm{mgr}}{\left(\mathrm{L}^2-\mathrm{r}^2\right)}$$
C
$$\frac{\sqrt{\mathrm{L}^2-\mathrm{r}^2}}{\mathrm{mgL}}$$
D
$$\frac{\mathrm{mgL}}{\sqrt{\mathrm{L}^2-\mathrm{r}^2}}$$
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