1
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two long conductors separated by a distance '$$\mathrm{d}$$' carry currents $$I_1$$ and $$I_2$$ in the same direction. They exert a force '$$F$$' on each other. Now the current in one of them is increased to two times and its direction is reversed. The distance between them is also increased to $$3 \mathrm{~d}$$. The new value of force between them is

A
$$-2 \mathrm{~F}$$
B
$$\frac{\mathrm{F}}{3}$$
C
$$\frac{-2 \mathrm{~F}}{3}$$
D
$$\frac{-\mathrm{F}}{3}$$
2
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The a.c. source is connected to series LCR circuit. If voltage across $$R$$ is $$40 \mathrm{~V}$$, that across $$\mathrm{L}$$ is $$80 \mathrm{~V}$$ and that across $$\mathrm{C}$$ is $$40 \mathrm{~V}$$, then the e.m.f. '$$e$$' of a.c. source is

A
40 V
B
40$$\sqrt2$$ V
C
80 V
D
160 V
3
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

In the study of transistor as an amplifier if $$\alpha=\frac{I_C}{I_E}=0.98$$ and $$\beta=\frac{I_C}{I_B}=49$$, where $$I_C, I_B$$ and $$\mathrm{I}_{\mathrm{E}}$$ are collector, base and emitter current respectively then $$\left(\frac{1}{\alpha}-\frac{1}{\beta}\right)$$ is equal to

A
zero
B
$$\frac{1}{2}$$
C
2
D
1
4
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A liquid drop of radius '$$R$$' is broken into '$$n$$' identical small droplets. The work done is [T = surface tension of the liquid]

A
$$4 \pi \mathrm{R}^2\left(\mathrm{n}^{\frac{2}{3}}-1\right) \mathrm{T}$$
B
$$4 \pi R^2\left(n^{\frac{1}{3}}-1\right) T$$
C
$$4 \pi R^2\left(1-n^{\frac{1}{3}}\right) T$$
D
$$4 \pi \mathrm{R}^2\left(1-\mathrm{n}^{\frac{2}{3}}\right) \mathrm{T}$$
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